#include<stdio.h> #include<conio.h> int main() { double n,sum=0,i; printf("\n Please Give The Value of N: "); scanf("%lf",&n); for(i=1;i<=n;i++) { sum = sum + (1/i); if(i==1) printf("\n 1 +"); else if(i==n) printf(" (1/%f) ",i); else printf(" (1/%f) + ",i); } printf("\n\n THE SUM OF THIS SERIES IS %.2lf",sum); getch(); return 0; }
Monday, May 16, 2016
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